Math, asked by ekalavyaachanta, 1 year ago

The simple interest and compound interest on a certain sum of money for 2 years are rs.8000 and rs.8800 respectively.find the sum and rate% per annum ?


jainsumit2014: difference between SI and CI ???

Answers

Answered by kooper
2
S.I=P*R*T/100₉
8,000=P*R*2/100
8,000*100/2=P*R
P*R=4,00,000             ........(i)


C.I=P(1+R/100)
²  -P
8,800=P((100+R)/100)²  -P
⇒8,800 = P((100+R)²/10,000) - P
⇒8,800 = {P(100+R)² - 10,000P)/10,000
⇒8,800*10,000 = P(10,000+R² + 200R) - 10,000P           [(a+b)² = a² + b² + 2ab]
⇒8,800*10,000 = 10,000P + PR² + 200PR -10,000P
⇒8,800*10,000 = PR²+200PR
Substituting value of P*R,
⇒8,800*10,000 = 4,00,000R+8,00,00,000
⇒8,80,00,000-8,00,00,000 = 4,00,000R
⇒80,00,000 = 4,00,000R
⇒R = 80,00,000/4,00,000
⇒R = 20%
⇒P = Rs. 20,000


HOPING THAT IT WILL HELP YOU!!!

kooper: plz mark it as the brainliest
ekalavyaachanta: Thanq.......is there any shortcut for this qn?
kooper: if u want to make the question easier, then you can remove two zeroes from 8800 and 8000 to make them 88 and 80 and then solve the question, and at the end, add to zeroes to the final answer
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