Question

the simple interest on $4500 for 2yrs at 12% p.ais
​

Answer 1

SI = Principal x Rate of Interest x Time/100

= 4500 x 12 x 2 / 100

=45 x 24

=1080$

Answer 2

$\bf \:\huge \red{ \mathfrak {AηsωeR}}$

$\begin{gathered}\sf Given \: that \begin{cases} & \sf{Principal \: = \bf{ 4500 \: }} \\ & \sf{Rate \: of \: interest \: = \bf{12 \: percent \: p.a}} \\ & \sf{Time \: = \bf{2 \: year's}} \end{cases}\\ \\\end{gathered}$

$\begin{gathered}\begin{gathered}\bf  To \:  Find :-  \begin{cases} &\sf{Simple \: Interest}  \end{cases}\end{gathered}\end{gathered}$

${\large{\bold{\rm{\underline{Using \; concepts}}}}}$

★ Formula to find Simple Interest

${\large{\bold{\rm{\underline{Using \; formulas}}}}}$

${\sf{\star \: Simple \: interest \: = \: \dfrac{P \times R \times T}{100}}}$

Where,

• ★ P denotes Principal

• ★ R denotes Rate

• ★ T denotes Time

~ Let's use the formula to find Simple Interest and implied the values and let substitute the values..!

$:\implies \sf{\sf{ Simple \: interest \: = \: \dfrac{P \times R \times T}{100}}}$

$:\implies \sf{\sf{ Simple \: interest \: = \: \dfrac{4500 \times 12 \times 2}{100}}}$

$:\implies \sf \: \boxed{ \red{ \bf \: Simple \: Interest \: = \: \: 1080}}$