Math, asked by diy21, 1 year ago

The simple interest on a certain amount of money at a certain rate of interest for 4 years is rs.160.Find the simple interest on double the amount of money at the same rate for 2 years.

Answers

Answered by Anonymous
50
Hi.

Here is your answer---

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Given---
In First Case,

Simple Interest(S.I.) = Rs. 160
Time(T) = 4 years.

Let the Principle be Rs. P and rate of interest be R%

Using the Formula,

   S.I. = (P × R × T) ÷ 100
  160  = (P × R × 4) ÷ 100
  P × R = 16000/4
  P × R =  4000 ------------------------------eq(i)

In Second Case---

Principal(P')= 2 × P
Rate of Interest  = R%
Time(T) = 2 years.

Using the Formula,

 S.I. = (P' × R × T) ÷ 100
 S.I. = 2 × P × R × 2) ÷ 100

Putting the value of eq(i) into this,

S.I. =  (2 × 4000 × 2) ÷ 100
       = Rs. 160

Thus, the Simple Interest will be Rs. 160.

______________________

Hope it helps.

Have a nice day.
Answered by sanscruti2010
5

Answer:

160

Step-by-step explanation:

is answer.

this is your answer

I Hope It's helpful

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