Question

the simple interest on a certain sum for 1 1/2 years at 10 percent per annum is rs 112.50. Find the sum

Answer 1

SI=P*r*t/100
112.5=p*11*10/2*100
112.5=110p/200
112.5*200/110=p
204.54=p

principal is 204.54

Answer 2

$Given,....\\Principal(P) = ?\\Rate(R) = 10\%\\Time(T) = 1\frac{1}{2}=\frac{2}{3}\\\\We \ know,\\S.I = \frac{P\times R\times T}{100}\\\\112.50=\frac{P\times 10 \times \frac{3}{2}}{100}\\\\\frac{112.50\times100}{5\times 3} = P\\\\Rs.750 = P\\or\\\boxed{\boxed{P= Rs.750}}$