Question

the simple interest on a certain sum for 3 years is at 14% per annum is rs 235.20 the sum is

Answer 1

$simple \: interest = p \times r \times t \div 100 \\ 235.20 = p \times 14 \times 3 \div 100 \\ 235.20 = 21p \div 50 \\ by \: cross \: multiplication \\ 235.20 \times 50 = 21p \\ 11760 = 21p \\ threfore \: \\ p = 11760 \div 21 = 560 \\ \\ so \: the \: sum \: is \: rs560$
Mark as brainleist

Answer 2

Hello............ ^_^

Here is your answer...

Given :-
Rate of interest = 14%per annum
Time = 3 years
Simple Interest (S.I) = Rs. 235.20

Let Principal (P) = 'P'

$S.I = \frac{P \times R \times T}{100} \\ \\ = > 235.20 = \frac{P \times 14 \times 3}{100} \\ \\ (14 \times 3 = 42) \\ \\ = > 235.20 = \frac{42 \: P}{100} \\ \\ = > 235.20 \times 100 = 42 \: P \\ \\ = > 23520 = 42 \: P \\ \\ = > \frac{23520}{42} = P \\ \\ = > 560 = P$
Hence, Principal (P) = Rs.560


CHECK
$S.I = \frac{P \times R \times T}{100} \\ \\ S.I = \frac{560 \times 14 \times 3}{100} \\ \\ (560 \times 14 \times 3 = 23520) \\ \\ S.I = \frac{23520}{100} \\ \\ S.I = 235.20$


Hope it helps............ ^_^