the simple interest on a certain sum of money for 2 years at 10% per annum is 1,600 the first question find sum. second question amount due after 3 years and above sum of the same interest and compound annually answer for the first q: principal equal to 8000 and the second question amount is equal to 10648 is the answer correct or wrong
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n = 2 years, r = 10%, p= 1600
SI = pnr/100
=1600 x 2 x 10 / 100
= rs. 320
Amount = P + SI
= 1600 + 320
= rs.1920
for 3 years
SI = 1600 x 3 x 10 / 100
= rs. 480
Amount due at 3 years = 1600 + 480 = rs. 2080
Compound interest-> Amount = p(1 + r/100)^n
Amount = 8000 ( 1 + 10/100)^2
= 8000 x 1.1 x 1.1
= 8000 x 1.21
=rs. 9680
so, C.I = 9680 - 8000 = 1680
The given answer (Rs. 10648) is wrong because we got Rs.9680
SI = pnr/100
=1600 x 2 x 10 / 100
= rs. 320
Amount = P + SI
= 1600 + 320
= rs.1920
for 3 years
SI = 1600 x 3 x 10 / 100
= rs. 480
Amount due at 3 years = 1600 + 480 = rs. 2080
Compound interest-> Amount = p(1 + r/100)^n
Amount = 8000 ( 1 + 10/100)^2
= 8000 x 1.1 x 1.1
= 8000 x 1.21
=rs. 9680
so, C.I = 9680 - 8000 = 1680
The given answer (Rs. 10648) is wrong because we got Rs.9680
nandhu16:
friend i have a doubt that simple interest=1600konw?
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