The simple interest on a certain sum of money for 3 years 5% pers annum is 1200 the compound intrest for same period is
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Hey sup,
r=5%.
t=3years.
Let principal be p.
SI=(p×r×t)/100.
=>1200=(p×5×3)/100.
=>1200×100=15p.
=>p=120000/15.
=>p=8000.
A=p(1+r/100)^t.
=8000(1+5/100)^3.
=8000(105/100)^3.
=8000(21/20)^3.
=8000×21/20×21/20×21/20.
=21×21×21.
=9261.
CI=A-p.
=9261-8000.
=1261.
So the compound interest is 1261.
Hope it helps.
r=5%.
t=3years.
Let principal be p.
SI=(p×r×t)/100.
=>1200=(p×5×3)/100.
=>1200×100=15p.
=>p=120000/15.
=>p=8000.
A=p(1+r/100)^t.
=8000(1+5/100)^3.
=8000(105/100)^3.
=8000(21/20)^3.
=8000×21/20×21/20×21/20.
=21×21×21.
=9261.
CI=A-p.
=9261-8000.
=1261.
So the compound interest is 1261.
Hope it helps.
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