the simple interest on a sum for 2 years at 10 percent annum is rs 1000. the same amount is borrowed at 8 percent per annum and compounded annually. find the compound interest and the amount to be paid after 2 years
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Step-by-step explanation:
it is given that
period =2 years
Rate = 10% p.a.
we know that
Sum=(SI×100)/(r×n)
Substituting the value
=(1600×100)/(10×2)
=8000
Here
Amount after 3yearz=p(1+r/100)n
Substituting the value
=8000(1+10/100)³
By further calculations
=8000×11/10×11/10×11/10
=10645
so the compound interest =A-p
Substituting the value
=10648- 8000
=2648
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