Question

The simple interest on a sum of money for 2 years at 6 % p.a. is rupees 900.what will be the compond interest on that sum at the same rate and for the same period .
Plz ans this fast......

Answer 1

S.I.= PRT/100
Rs 900= (P×6×2)/100
Rs 900×100/12= P
Rs 7500= Principal
Amount= Principal(1+r/100)^n
A= Rs 7500(1+6/100)^2
A= 7500×106/100×106/100
Amount= Rs 8427
C.I.= A-P
= Rs(8427-7500)= Rs 927
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Answer 2

$\huge{ \underline{ \overline{ \mid{ \mathfrak{ \purple{ \: \: SOLUTION \: \: } \mid}}}}}$

$\mathfrak{Suppose,} \\ \\ \mathtt{</p><p>The \: \: sum \: \: of \: \: money \: \: be \: \: Rs. \: P} \\ \\ \underline{ \mathfrak{ \: Given, \: }} \\ \\ \mathtt{Rate \: \: of \: \: Interest, r = 6\%} \\ \\ \mathtt{No. \: \: of \: \: years, n = 2 \: \: years.} \\ \\ \mathtt{S.I. = Rs. 900 }$

$\underline{ \mathfrak{ \: \: We \: \: know \: \: that, \: }} \\ \\ \: \: \: \: \: \: \: \: \mathtt{S.I. = \frac{P \times r \times n}{100} } \\ \\ \mathtt{\Longrightarrow \: 900 = \frac{ P\times 6 \times 2}{100} } \\ \\ \mathtt{\Longrightarrow \:900 = \frac{12P}{100} } \\ \\ \mathtt{\Longrightarrow \:12P = 90000 } \\ \\ \mathtt{\Longrightarrow \: P= \frac{90000}{12} } \\ \\ \mathtt{\therefore \: \: \: P = 7500} \:$

$\bold{Hence,} \\ \: \: \: \: \: \: \: \bold{The \: \: sum \: \: of \: \: money = Rs. \: 7500}</p><p>$

$\mathfrak{Now,} \\ \\ \underline{ \mathfrak{ \: \: We \: \: know \: \: that, \: \: }} \\ \\ \mathtt{C.I. = A - P } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \mathtt{ = P(1 + \frac{r}{100}) {}^{n} - P } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \mathtt{ =P(1 + \frac{r}{100} ) {}^{n} - 1 } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \mathtt{ = 7500 \times (1 + \frac{6}{100}) {}^{2} - 1 } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \mathtt{ = 7500 \times ( \frac{106}{100} ) {}^{2} - 1} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \mathtt{ = 7500 \times ( \frac{11236}{10000} - 1)} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \mathtt{ = 7500 \times ( \frac{11236 - 10000}{10000} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \mathtt{ = 7500 \times \frac{1236}{10000} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \mathtt{ = \frac{9,270,000}{10000} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \mathtt{ = 927}$

$\bold{Hence,} \\ \: \: \: \bold{Compound \: \: interest \: \: of \: \: the \: \: sum \: \: = Rs. \: 927}</p><p>$