Math, asked by brightdivyanshi3711, 1 year ago

The simple interest on a sum of money for 2 years at 8% per annum is 2400 what will be the compound interest on that from at the same rate and for the same period

Answers

Answered by fiercespartan
215

Hey there!!

Let us take the principle as = x

Term = 2 years

Rate = 8%

Simple interest = 2400 rupees

Formula for simple interest = ( principle × term × rate ) ÷ 100

= ( x × 2 × 8 ) ÷ 100

= ( 16 x ) ÷ 100

= ( 8 x ) ÷ 50

= ( 4 x ) ÷ 25

( 4 x ) ÷ 25 = 2400

( 4 x ) = 2400 × 25

x = ( 2400 × 25 ) ÷ 4

x = ( 600 × 25 )

x = rupees 15,000

Principle = rupees 15,000

Compound interest =

principle × ( 1 + ( r ÷ 100 ) ) ^ n

15,000 × ( 1 + ( 8 ÷ 100 ) ) ²

15,000 × ( 1 + ( 4 ÷ 50 ) ) ²

15,000 × ( 54 ÷ 50 ) ²

15,000 × ( 54 ÷ 50 ) × ( 54 ÷ 50 )

150 × ( 54 ÷ 5 ) × ( 54 ÷ 5 )

30 × ( 54 ) × ( 54 ÷ 5 )

( 6 ) × ( 54 ) × ( 54 )

= 17,496

17,496 is the amount

Amount = Principle + interest

17,496 = 15,000 + interest

2,496 = interest

Compound interest = 2,496

Hope my answer helps!

#BeBrainly

@sid071


Prakhar2908: Great.
fiercespartan: Thanks!
Mankuthemonkey01: Awesome Bhaijaan ✌️
fiercespartan: Thanks!
Answered by Shubhendu8898
131

Given,

For simple interest

Time (t)= 2 years

rate(r) = 8%

simple interest = Rs. 2400

We know that ,

 Simple\  Interest = \frac{ p*r*t}{100} \\ \\ 2400 = \frac{p*8*2}{100} \\ \\ p = \frac{240 *10^{3}}{16}  \\ \\   p = 15*10^{3}  \\ \\ p = Rs. 15000

For compound interest

 Amount = p(1 + \frac{r}{100})^{n}  \\ \\  = 15000(1 + \frac{8}{100})^{2} \\ \\ = 15000(1 + \frac{2}{25})^{2}  \\ \\ = 15000(\frac{27}{25})^{2}  \\ \\ = Rs. 17496 <br />

Compound Interest = Amount - Principle

= 17496 - 15000

= Rs. 2,496


Prakhar2908: Nice answer sir.
Similar questions