Math, asked by anbhowmick109, 3 months ago

The simple interest on a sum of money to
2 years at 12% per annum is rs. 1380. Find
(1) the sum of money and
(in) the compound interest on this sum for
one year payable half yearly at the same
rate​

Answers

Answered by Aarohishrma
2

Step-by-step explanation:

Answer

It is given that

Simple Interest (SI) = 1380

Rate of interest (R) = 12% p.a.

Period(T)= 2 years

(i) We know that

Sum(P) = (SI×100)/(R×T)

Substituting the values

=(1380×100)/(12×2)

= 5750

(ii) Here

Principal (P)= 5750

Rate of interest (R)= 12% p.a or 6% half- yearly

Period (n) = 1 year - 2 half years

So we get

Amount (A)= P(1 + R/100)

Substituting the values

=5750(1+6/100)

2

By further calculation

= 5750×(53/50)

2

So we get

=5750×53/50×53/50

= 6460.70

Here

Compound interest = A- P

Substituting the values

= 6460.70−5750

= 710.70

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