Question

The simple interest on a surten sum 1 1/2 years at 10% per annum is ₹112.50. Find the sum

Answer 1

HERE , I DENOTE SI(SIMPLE INTEREST) , R(RATE) , T(TIME PERIOD) , P(PRINCIPAL).

HERE(IN THE PROBLEM) THE MEANING OF 'SUM' IS PRINCIPAL.

'SI' IS GIVEN , 'R' IS GIVEN , 'T' IS GIVEN.
WE HAVE TO FIND 'P'.

$p = \frac{si \: \times 100}{r \: \times \: t}$
si is rs.112.50 , r is 10% , t is 1 1/2 = (3/2) years
$p \: = \: \frac{112.50 \: \times 100}{10 \: \times \frac{3}{2} }$
$p = \frac{ 11250×100×2 }{10 \times 3 \times 100}$
$p \: = \frac{11250 \times 2}{10 \times 3}$
$p \: = \frac{11250}{3 \times 5}$
$p \: = \frac{11250}{15}$
$p \: = rs.750$
so your sum is rs.750

ANS = THE SUM IS RS.750.

HOPE IT HELPS YOU!!!!

Answer 2

Step-by-step explanation:

p=si×100/r×t

• si is rs. 112.50 , r is 10% , t is 1 1/2 = ( 3/2) years

p= 112.50 × 100/10 × 3/2

p=11250× 100×2/ 10 × 3× 100

p= 11250×2/10× 3

p= 11250/ 3×5

p= 11250/15

p= r.s 750

Ans = the sum is r.s 750