Math, asked by Sakharam11631, 10 months ago

The simple interest on any amount is 2/9 of principal. If number of year is twice the rate of interest then for how many years that amount was given

Answers

Answered by bhagyashreechowdhury
0

If a number of years are twice the rate of interest then the amount was given for 6\frac{2}{3} years.

Step-by-step explanation:

Let the principal be denoted as “P” and the no. of years be denoted as “T”.

It is given that,

The simple interest on any amount is 2/9th of the principal

i.e., S.I. = \frac{2}{9} * P ….. (i)

Also, the no. of years is twice the rate of interest (R),  

i.e., T = 2 * R  

⇒ R = \frac{T}{2} …. (ii)

The formula for the Simple Interest is given by,

S.I. = \frac{PRT}{100}

Substituting the values from (i) & (ii) in the formula, we get

\frac{2}{9} * P = [P * \frac{T}{2} *T] / 100

\frac{2}{9} = [\frac{T}{2} *T] / 100

⇒ T² = \frac{2 * 100 * 2}{9}

Taking square roots on both sides

⇒ T = \frac{20}{3} years

T = 6\frac{2}{3} years

Thus, the amount was given for 6\frac{2}{3} years.

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