Question

the simple interest on rs 500 at 10% p.a for 2 years is​

Answer 1

Answer:

answer will be - 100 rupees

Step-by-step explanation:

Principal 500rupees

Rate of interest- 10%

Time- 2 years

Now we know ,

S.I - PxRxT/100

(S.I stands for simple interest)

so,

S.I - 500x10x2/100

=>5x20

=> 100 rupees

Answer 2

Given:

• Principal (P) = 500 Rupees.

• Rate of interest (R) = 10% per annum.

• Time (T) = 2 years.

To Find:

• Simple Interest (S.I) = ?

Formula Used:

$\star \: \boxed{\sf\red{Simple \: Interest (S.I) = \frac{P \times R \times T}{100} }}$

Solution:

Placing Values,

$:\implies\bf{ \frac{500 \times 10 \times 2}{100} }$

$:\implies\bf{ \frac{500 \times 20}{100} }$

$:\implies\bf{ \frac{10000}{100} }$

$:\implies\bf{\dfrac{\cancel{10000}}{\cancel{100}}}$

$\sf\star \: \underbrace\orange{Simple \: Interest = 100 \: Rupees} \: \star$

Hence,

• Simple Interest (S.I) is 100 Rupees.

ExtraShots:

$\sf{Compound \: Interest (C.I) =a = p1 + \frac{r}{n} \: {n} ^{t} }$

Where,

• a = Amount.

• p = Principal.

• r = Annual Rate.

• m = Times/Year.

• t = times in a year.