Math, asked by prabh38, 1 year ago

the simple interest on rupees 1200 from January 4 1984 to May 29 1995 at 3% per annum in rupees

a. 14.40
b. 50.40
c. 15.40
d. 51.40

Answers

Answered by Khushisinghal
22
1200
1200 \\ 4january - 29may = 3 \: month \\ 25 \: days \\ 1984 - 1995 = 11 \: years \\  = 14.40
Answered by throwdolbeau
4

Answer:

Simple Interest = Rs. 410.40

Step-by-step explanation:

Principal = Rs. 1200

Rate of Interest = 3% per annum

                          = 0.03

Now, to find Simple Interest find time interval from January 4, 1984 to May 29, 1995

First find no of days from January 4 to May 29 = 4 months and 25 days

\text{In years = }\frac{4}{12}+\frac{25}{12\times 30}=0.40\thinspace{ years}

No. of year from 1984 to 1995 = 11 years

So, total time of Interest = 11.40 years

Now, Simple Interest = Principal × Rate × Time

⇒ Simple Interest = 1200 × 0.03 × 11.40

Hence, Simple Interest = Rs. 410.40

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