Question

The simple interest Rs3500 at 10% per annum for a certain period is Rs400 more than interest on Rs2500 at 10% per annum for same period. Find the time.question for 100 points

Answer 1

Given :-

$P_1 = ₹3500$

$P_2 = ₹2500$

Rate = 10%

Interest on ₹3500 = 400 + Interest on ₹2500

To Find :-

The time period

Solution :-

When principal is ₹2500 :-

$SI\: =\: {\dfrac{P \times R \times T}{100}}$

On inserting the values in the formula

We get ,

$SI\: =\: {\dfrac{2500 \times 10 \times T}{100}}$

= 250t

When principal is ₹3500 :-

$SI\: =\: {\dfrac{P \times R \times T}{100}}$

On inserting the values in the formula

We get ,

$SI\: =\: {\dfrac{3500 \times 10 \times T}{100}}$

= 350t

According to question,

SI for ₹3500 principal = 400 + 250t

=> 350t = 400 + 250t

=> 350t - 250t = 400

=> 100t = 400

$=>\: t\: =\: {\dfrac{400}{100}}$

=> t = 4

Therefore, total time period was 4 years.