Question

the simple intrest on ruppes 10,000 for 10 years at 5% simple intrest=

give full explanation
otherwise it will be reported​

Answer 1

$\huge\mathfrak \blue{answer}$

Principal amount (P)=Rs.10000

Period(N)=5years

Rate of interest (R)=10%

Simple interest=(P*N*R)/100=(10000*5*10)/100=500000/100=Rs.5000

Amount= principal + simple interest=10000+5000=Rs.15000

For compound interest

A=P*(1+R/100)^N=10000*(1+10/100)^5=10000*(1+0.1)^5=10000*(1.1)^5 =10000*1.61051=Rs16105.10

Compound interest=amount- principal=16105.10–10000=Rs.6105.10

Answer: simple interest=Rs.5000

Compound interest =Rs.6105.10

Answer 2

Given :

Principal (p) = ₹ 10,000

Time (t) = 10years

Rate (R) = 5%

$S.I = \frac{p.r.t}{100} \\ \\ ➠ S.I = \frac{10,000 × 5 × 10}{100} \\ \\ ➠S.I = \frac{500000}{100} \\ \\➠S.I = ₹5000$

Therefore, The simple Interest is ₹ 5000