Question

The simple pendulum in Figure 3 oscillates with SHM. The angle θ made by the string with the vertical as a function of time is ()=max +0
The pendulum starts to oscillate at maximum angle (8.0°). Find the time t when the pendulum reaches 4.0° on the opposite side and its velocity

Answer 1

Answer:

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Answer 2

The highest tension is at O, and the lowest tension is at A.

K.E. at O=P.E. at A 12mv2=mgh=mgl(1cos) v2=2gl(1cos) v2=2gl(1cos) v2=2gl(1cos) v2=2gl(1cos) v2=2gl(1cos) v2=2gl(1cos) v2=2gl(1cos

Tmax=mg+mv2l \s=mg+ml[2gl(1−cosθ)]

=3mg2mgcos and Tmin=mgcos Tmax=3Tmin Tmax=3Tmin 3mg2mgcos=3mgcos 3=5coscos=35