the simple pendulum whose length is 20 cm is suspended from the ceiling of a lift which is rising up with an acceleration of 3 M per second square calculate the time period of the pendulum
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T=2π√[l/g]
T=2π√[20/(3+9.8)]
=7.85
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3
Answer:
T=2π√[l/g]
=2π√[0.2/(3+9.8)] (20cm should be converted to meters therefore 0.2m)
=2×3.14×0.125
=0.785 s
:)
Explanation:
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