Question

The simplest rationalisation factor of
$\sqrt{27}$
Is?
Its option is
A.
$\sqrt{6}$
B.
$\sqrt{3}$
C.

26

D.

3



​

Answer 1

$\sqrt{27} = \sqrt{9 \times 3} = \sqrt{9} \times \sqrt{3} = 3 \sqrt{3}$

$to \: rationalise \: it \: we \: must \: multiply \: \sqrt{3}$

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ANSWER: B) ROOT 3