Question

The Simplification of Y = AB’ + (A’ + B)C is

Answer 1

Answer:

Y=(A+B)(A+C′)(B′+C′)Y=(A+B)(A+C′)(B′+C′)

=(AA+AC′+AB+BC′)(B′+C′)=(AA+AC′+AB+BC′)(B′+C′)

=(A+AC′+AB+BC′)(B′+C′)=(A+AC′+AB+BC′)(B′+C′)

=(A(1+C′+B)+BC′)(B′+C′)=(A(1+C′+B)+BC′)(B′+C′)

=(A+BC′)(B′+C′)=(A+BC′)(B′+C′)

=AB′+AC′+B′BC′+BC′C′=AB′+AC′+B′BC′+BC′C′

=AB′+AC′+0+BC′=AB′+AC′+0+BC′

=AB′+AC′+BC