Math, asked by nandu561, 9 months ago


The simplified value of 16x-3y2 x 8-'x'y
(a) 2xy
(b) xy/2
The value of (0127-1/3,
1/5​

Answers

Answered by Agastya0606
4

Given: The correct term is 16x^-3 y^2 x 8^-1 x^3 y^-2

To find: The value of the given term.

Solution:

  • Now we have given the term as:

                    16x^-3 y^2 x 8^-1 x^3 y^-2

  • We can rewrite it as:

                    ( 16 × y² / x³ ) × ( x³ / 8 × y² )

  • Now merging both, we get:

                    ( 16 × y² × ³ ) / ( x³ × 8 × y² )

  • Cancelling similar terms, we get:

                    16/8 = 2

Answer:

              So the value of the given term is 2.

Answered by brainlyvirat187006
2

Answer:

Given: The correct term is 16x^-3 y^2 x 8^-1 x^3 y^-2

To find: The value of the given term.

Solution:

Now we have given the term as:

                    16x^-3 y^2 x 8^-1 x^3 y^-2

We can rewrite it as:

                    ( 16 × y² / x³ ) × ( x³ / 8 × y² )

Now merging both, we get:

                    ( 16 × y² × ³ ) / ( x³ × 8 × y² )

Cancelling similar terms, we get:

                    16/8 = 2

Answer:

              So the value of the given term is 2.

꧁༒BRAINLYVIRAT187006༒꧂

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