Question

The simultaneous equation 3x + 5y = 16 and
4x-y
6 have​

Answer 1

Explanation:

3x + 5y = 16 ....(i)

4x - y = 6 ...(ii)

Multiply (ii) with '5'

3x + 5y = 16

20x - 5y = 30

Adding both: 23x = 46

x = 46/23 = 2

Substitute this 'x' value in any equation.

'x' in (ii)== 4*2 - y = 6

8 - y = 6

y = 2

Hence x = y =2

Answer 2

$\huge\bold\purple{ solution }$

$3x + 5y = 16 \\ 4x - y = 6$

$\huge\bold\red{ ♡answer }$

$3x + 5y = 16 - - (i) \\ \\ 4x - y = 6 - - (ii)$

equation (ii)×5

$3x + 5y = 16 \\ 20x - 5y = 30$

______________________

$23x = 46 \\ \\ x = \frac{46}{23} \\ x = 2$

X= 2 put in equation (I)

$4x - y = 6 \\ \\ 4 \times 2 - y = 6 \\ \\ 8 - y = 6 \\ \\ - y = - 2 \\ y = 2$

hence X= 2 and y=2