Question

the simultaneous
Find the value
of Dx, for solving
equations 3x + 4y = 8; x-2y=5 by cramer's sule​

Answer 1

$\underline{\textsf{Given:}}$

$\mathsf{3x+4y=8}$

$\mathsf{x-2y=5}$

$\underline{\textsf{To find:}}$

$\textsf{Solution of the simultaneous equations by Cramer's rule}$

$\underline{\textsf{Solution:}}$

$\mathsf{\triangle=\left|\begin{array}{cc}3&4\\1&-2\end{array}\right|}$

$\mathsf{\triangle=-6-4=-10}$

$\mathsf{{\triangle}x=\left|\begin{array}{cc}8&4\\5&-2\end{array}\right|}$

$\mathsf{{\triangle}x=-16-20=-36}$

$\mathsf{{\triangle}y=\left|\begin{array}{cc}3&8\\1&5\end{array}\right|}$

$\mathsf{{\triangle}y=15-8=7}$

$\textsf{By Cramer's rule}$

$\mathsf{x=\dfrac{{\triangle}x}{\traingle}=\dfrac{-36}{-10}=\dfrac{36}{10}}$

$\mathsf{y=\dfrac{{\triangle}y}{\traingle}=\dfrac{7}{-10}=\dfrac{-7}{10}}$

$\underline{\textsf{Answer:}}$

$\textsf{The solution is}$

$\mathsf{x=\dfrac{36}{10}\;\;\&\;\;y=\dfrac{-7}{10}}$

Find more:

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By Using cramer's rule solve the given linear equations.

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Answer 2

Answer:

In cramer's rule of a

1

x+b

1

y=c

1

,a

2

x+b

2

y=c

2

x=

D

D

x

=

∣

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∣

a

1

a

2

b

1

b

2

∣

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c

1

c

2

b

1

b

2

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y=

D

D

y

=

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a

1

a

2

b

1

b

2

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a

1

a

2

c

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c

2

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D

x

=

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c

1

c

2

b

1

b

2

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So here D

x

=

∣

∣

∣

∣

∣

∣

8

5

4

−2

∣

∣

∣

∣

∣

=−36