Math, asked by pranjalpradhan56, 10 months ago

the simultaneous
Find the value
of Dx, for solving
equations 3x + 4y = 8; x-2y=5 by cramer's sule​

Answers

Answered by MaheswariS
19

\underline{\textsf{Given:}}

\mathsf{3x+4y=8}

\mathsf{x-2y=5}

\underline{\textsf{To find:}}

\textsf{Solution of the simultaneous equations by Cramer's rule}

\underline{\textsf{Solution:}}

\mathsf{\triangle=\left|\begin{array}{cc}3&4\\1&-2\end{array}\right|}

\mathsf{\triangle=-6-4=-10}

\mathsf{{\triangle}x=\left|\begin{array}{cc}8&4\\5&-2\end{array}\right|}

\mathsf{{\triangle}x=-16-20=-36}

\mathsf{{\triangle}y=\left|\begin{array}{cc}3&8\\1&5\end{array}\right|}

\mathsf{{\triangle}y=15-8=7}

\textsf{By Cramer's rule}

\mathsf{x=\dfrac{{\triangle}x}{\traingle}=\dfrac{-36}{-10}=\dfrac{36}{10}}

\mathsf{y=\dfrac{{\triangle}y}{\traingle}=\dfrac{7}{-10}=\dfrac{-7}{10}}

\underline{\textsf{Answer:}}

\textsf{The solution is}

\mathsf{x=\dfrac{36}{10}\;\;\&\;\;y=\dfrac{-7}{10}}

Find more:

Find x,y,z using cramers rule, if x-y+z=4, 2x+y-3z=0 and x+y+z=2

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By Using cramer's rule solve the given linear equations.

x + y-Z=1; 8x + 3y - 6Z=1; 4x - y +3Z =1​

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Answered by dipakapatil40166
3

Answer:

In cramer's rule of a

1

x+b

1

y=c

1

,a

2

x+b

2

y=c

2

x=

D

D

x

=

a

1

a

2

b

1

b

2

c

1

c

2

b

1

b

2

y=

D

D

y

=

a

1

a

2

b

1

b

2

a

1

a

2

c

1

c

2

D

x

=

c

1

c

2

b

1

b

2

So here D

x

=

8

5

4

−2

=−36

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