Question

The sine of the angle between two vectors i-2j+3k and 2i+j+k is

Answer 1

Hello dear!!

Here's your answer

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First let us find cos angle between both

cos x = a.b / (mod a . mod b )

a.b = 2 - 2 + 3 = 3

mod a = root 14

mod b = root 6

cos x = 3 / root 84


now sin x = 9 / root 84



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Hope it helped you!!!

Sindhu

Answer 2

Step-by-step explanation:

Cos x=A.B/|A|.|B<

A.B=2-2+3=3

|A|=sqrt14;|B|=sqrt6

Cos x=3/sqrt84

since sin x =sqrt 1-cos^2 x

we get sinx =sqrt 1-9/84=sqrt84-9/84

sqrt 75/84 =sqrt 25×3/4×21 =5/2sqrt7