The single discount of discount series 15%,10%, and 8% is
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Answered by
6
Let the price of the object be x.
Now after the discount of 15% the discounted price of the object will become
x-x(15/100) = x(1-(15/100))
= x(85/100)
So the net discounted price will be
x(85/100)(90/100)(92/100)
=x(703800/1000000)
The net discount
x-x(703800/1000000)
= x(296200/1000000)
Net percentage discount
(296200/1000000)x100
=29.62%
Now after the discount of 15% the discounted price of the object will become
x-x(15/100) = x(1-(15/100))
= x(85/100)
So the net discounted price will be
x(85/100)(90/100)(92/100)
=x(703800/1000000)
The net discount
x-x(703800/1000000)
= x(296200/1000000)
Net percentage discount
(296200/1000000)x100
=29.62%
Answered by
0
Given : discount series 15 % 10% and 8%
To Find : single discount
Solution:
Let say Amount before discount = 1000X
15 % discount = (15/100) 1000X = 150X
Amount after 1st discount = 1000X - 150X = 850X
10% discount == (10/100) 850X = 85X
Amount after 2nd discount = 850X - 85X = 765X
8% discount = (8/100) 765X = 61.2X
Final Amount = 765X - 61.2X
= 703.8X
Net discount = 1000X = 703.8X
= 296.2X
Single Discount = (296.2X/1000X) * 100
= 29.62 %
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