Question

The single-phase circuit has supply voltage of Vs = 240 V (rms), the system frequency is 50 Hz, R = 0.975 Ω, L = 22 mH (ωL = 2.57 Ω) and the load is R-L comprising of an 9.75 Ω resistor and a 50.6 mH inductor (ωL = 26.66 Ω). With the system operating in the steady state, the switch S is suddenly closed creating a short circuit. Calculate the value of current during fault condition

Answer 1

use formula I=V/root(R^(2)+(1/ωC) - ωL)