Question

The singular points for differential equation is given by x®(x2 - 1) - x(x+1) - x(x – 1)y = 0

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Answer 1

Answer:

Finding Singular Points

p(x) = Q(x)/P(x)

q(x) = R(x)/P(x)

the singular points occur where Q(x)/P(x) and/or R(x)/P(x) become unbounded