Math, asked by pk866438, 6 hours ago

The singular solution of y = sin (y-xp) is
A) y = 1(x-1+sin 4-1 1x^2-1/x
B) y=Vx^2-1 + sin^-1Vx^2-1/x
C) y=Vx^3-2 + sin^-1Vx^2-1/x
D) None of these
D​

Answers

Answered by yashraj2201in
0

sorry I m in 8th so I can't answer

Answered by 17sw010432
0

The singular solution of y = sin (y-xp)

Step-by-step explanation:

y=cx+sin-1 c

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