the situation shown in figure is equivalent to
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The answer is 3. See explantation below ✓
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The situation shown in figure is equivalent to option 3 as posted in diagram
1.As both resistors are in parallel
So req=1/r1+1/r2
=1/2+1/2=1ohm
2.As both cells are in parallel
Eeq=E1r1+E2r2/r1+r2
=(10*2-4*2)/2+2
=3v
Therefore the correct option corresponding to these values is option 3
with a cell of 3v and resistor of 1ohm
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