The sixth term of an A.P. is 32 while the 10th term is 48. Find the common difference and the
21st term
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Let the first term be x and the common difference be d
Therefore, sixth term in terms of x and d= x+5d
10th term in terms of x and d= x+9d
According to the problem, x+5d=32 and x+9d=48
Difference between the two equation we get, 4d=16
=>d=4
Therefore, x=32-5d=32-20=12
Therefore, 21st term=x+20d=12+20*4=92
Answer: The common difference is 4 and 21st term is 92.
Therefore, sixth term in terms of x and d= x+5d
10th term in terms of x and d= x+9d
According to the problem, x+5d=32 and x+9d=48
Difference between the two equation we get, 4d=16
=>d=4
Therefore, x=32-5d=32-20=12
Therefore, 21st term=x+20d=12+20*4=92
Answer: The common difference is 4 and 21st term is 92.
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