Question

the sixth term of an arithmaetc progression is 23 and the fifteenth term is 66 find first term and common difference​

Answer 1

Answer:

Step-by-step explanation:

Given

$t_{6} =23\\ a+5d=23$ -------1  we know that  $t_{n} =a+(n-1)d$

$t_{15}= 66\\a+14d = 66$-------2

2-1

$9d=43\\d=43/9 \\a+5(43/9)=23\\9a+215=207\\9a=-8\\a=-8/9$