The sixth yerm of an ap is -10 and tenth term is -26 find 15th term
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Hi
Here is ur answer
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a6 = -10
a + (6-1)d = -10
a + 5d = -10 ------------(1)
a10 = -26
a + (10-1 )d = -26
a + 9d = -26 --------------(2)
Solving both by using elimination method
We get,
d = - 16 / 4
d = -4
Then substitute d in equation 1 or 2
( I am substituting in 1)
a + 5 * -4 = -10
a + (-20) = -10
a = -10 +20
a = 10
Therefore, to find a15
an = a + (n-1) d
a15 = 10 + ( 15-1 ) (-4)
= 10 + 14 (-4)
= 10 - 56
= - 46
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Hope it helps U
Hope it helps U
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