The size of an object by a convex lens of focal length 20 cm is observed to be reduced to 1/3rd of its size.Find the distance of the object from the optical centre of the lens.
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answer : object distance from the optical centre of the lens is 80cm.
explanation : focal length of convex lens , f = +20cm
a/c to question,
size of image = 1/3 × size of object.
so, magnification , m = -1/3
we know, magnification of lens , m = v/u
so, v/u = -1/3
so, v = -u/3 ........(1)
now applying lens maker formula,
1/v - 1/u = 1/f
or, 1/(-u/3) - 1/u = 1/20
or, -3/u - 1/u = 1/20
or, u = -80 cm
hence, object is placed 80cm from the pole of convex lens.
explanation : focal length of convex lens , f = +20cm
a/c to question,
size of image = 1/3 × size of object.
so, magnification , m = -1/3
we know, magnification of lens , m = v/u
so, v/u = -1/3
so, v = -u/3 ........(1)
now applying lens maker formula,
1/v - 1/u = 1/f
or, 1/(-u/3) - 1/u = 1/20
or, -3/u - 1/u = 1/20
or, u = -80 cm
hence, object is placed 80cm from the pole of convex lens.
Answered by
0
hi mate,
Solution: object distance from the optical centre of the lens is 80cm.
explanation : focal length of convex lens , f = +20cm
a/c to question,
size of image = 1/3 × size of object.
so, magnification , m = -1/3
we know, magnification of lens , m = v/u
so, v/u = -1/3
so, v = -u/3 ........(1)
now applying lens maker formula,
1/v - 1/u = 1/f
or, 1/(-u/3) - 1/u = 1/20
or, -3/u - 1/u = 1/20
or, u = -80 cm
hence, object is placed 80cm from the pole of convex lens.
i hope it helps you.
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