Question

The size of image of an object by a convex lens of focal length 20 cm os observed to be reduced 1/3 of its size.Find the distance of the object from the optical center of lens

Answer 1

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1/3=v/u

3u=v

Then since 1/v-1/u = 1/f

1/3u-1/u=1/20

-2/3u= 1/20

-40/3u=1

u=-40/3

13.34cm

Answer 2

hi mate,

Solution: object distance from the optical centre of the lens is 80cm.

explanation : focal length of convex lens , f = +20cm

a/c to question,

size of image = 1/3 × size of object.

so, magnification , m = -1/3

we know, magnification of lens , m = v/u

so, v/u = -1/3

so, v = -u/3 ........(1)

now applying lens maker formula,

1/v - 1/u = 1/f

or, 1/(-u/3) - 1/u = 1/20

or, -3/u - 1/u = 1/20

or, u = -80 cm

hence, object is placed 80cm from the pole of convex lens.

i hope it helps you.