Question

the sketch shows a rectangle ABCD.AB is twice the length of BC.E is the midpoint of AB.F is the midpoint of BC.Find the surface of each of these triangles. the answer is given as part of the rectangle.

Answer 1

Answer:

let's the one side of rectangle is ,a, and another side is twice if first side is ,2a,

In triengle EFB ,using phythagoruse thereom

(EF)2=(BE)2+(FB)2

(EF)2=(a/2)2+(2a)2

answer is ==a/2√5