Question

the slant height and curved surface area of one cone is twice that of the Other can find the ratio of their radius

please give me answer in notebook for image​

Answer 1

Step-by-step explanation:

Given:-

the slant height and curved surface area of one cone is twice that of the Other.

To find:-

find the ratio of their radius

Solution:-

Let the radius be "r1" units

and slant height "l1" units of the first cone

Then

Curved surface of a cone =πrl sq.units

Curved surface of the cone

=A1=π(r1)(l1) sq.units-----(1)

Let the radius of the other cone be "r2" units

and Slant height of the other be "l2" units

Curved surface area of the other cone

=A2=π(r2)(l2) sq.units-----(2)

Slant height of the first cone = 2 × slant height of the other cone

l1 = 2(l 2) units

Curved surface area of the first cone =

2×Curved surface area of the other cone

=>A1 = 2 A2

A1 = 2(π(r2)(l2))-------(3)

=>πr1l1 = 2π(r2)l2

=>πr1(2l2)=2(πr2l2)

=>2(πr1l2)=2(πr2l2)

=>r1 = r2

=>r 1/ r2 = 1/1

=>r1 : r2 = 1:1

Answer:-

The ratio of their radii is 1:1 for the given problem

there is no change in the radius , both are same in the ratio