the slant height of a conical mountain is 2.5 km and the area of its base is 1.54 CM square find the height of the mountain
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let the slant height of the Mountain be L
and the area of its base is 1.5 cm ^2
area of circle is Pi R Square
so pie r square =1.54 CM ^2
πr^2=1.54 cm^2
22/7 ×r ^2 = 1.54 ×7
r^2=0.49
r= 0.07 cm= 0.07÷ 100000=0.0000007= km
l ^2 = r^2 +h ^2
(2.5)²=(0.0000007)² +(h) ²
h²=6.25 - 0.0000000049= 6.25
h =√6.25 = 2.5 km
and the area of its base is 1.5 cm ^2
area of circle is Pi R Square
so pie r square =1.54 CM ^2
πr^2=1.54 cm^2
22/7 ×r ^2 = 1.54 ×7
r^2=0.49
r= 0.07 cm= 0.07÷ 100000=0.0000007= km
l ^2 = r^2 +h ^2
(2.5)²=(0.0000007)² +(h) ²
h²=6.25 - 0.0000000049= 6.25
h =√6.25 = 2.5 km
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