Question

the slant height of a conical tomh are 25 m and 14cm respectively. find cost of white washing its curved surface area at the rate of rs 210 per 100 m square​

Answer 1

Given:-

Slant Height of the conical tomb = 25 m

Diameter of the conical tomb = 14 cm

=> 14/100

=> 0.14 m

Radius of the conical tomb = 0.14/2 = 0.07 m

Find:-

cost of white washing the conical tomb of curved surface area at the rate of Rs. 210 per 100 m².

Solution:-

Curved surface area of the conical tomb = πrl

Substitute the known values in above formula

=> 22/7 × 0.07 × 25

=> 22 × 0.25

=> 5.5 m²

Cost of painting at the rate of Rs. 210 per 100 m² = (5.5 × 210)/100

=> 1155/100

=> 11.55

•°• Rs. 11.55 is the cost of white washing the conical tomb of curved surface area at the rate of Rs. 210 per 100 m²

Answer 2

$\huge\underline\blue{\rm Answer:}$

$\red{\boxed{\sf Cost\:of\: white-washing=Rs11.55}}$

$\huge\underline\blue{\rm Solution:}$

$\large\underline\pink{\sf Given: }$

• Slant height of conical tomb (l) = 25m

• Base radius of tomb (r) = 14/2 =0.0 7m

$\large\underline\pink{\sf To\:Find: }$

• Cost of white washing its curved surface area (CSA) at the rate of Rs 210 per 100 m square = ?

━━━━━━━━━━━━━━━━━━━━━━━━━

$\Large{\boxed{\sf CAS\:of\:tomb=πrl}}$

$\large\implies{\sf \frac{22}{7}×0.07×25}$

$\large\implies{\sf 5.5m^2}$

Curved surface area of conical tomb is $\sf{5.5m^2}$

Cost of white-washing $\sf{100m^2}$ area = Rs 210

Cost of white-washing $\sf{5.5m^2}$ is :-

$\large\implies{\sf \frac{210×5.5}{100}}$

$\large\implies{\sf Rs 11.55 }$

$\red{\boxed{\sf Cost\:of\: white-washing=Rs11.55}}$

Therefore,

It will cost Rs 11.55 while white-washing such a conical tomb.