Question

The slant height of a frustum of a cone is 4 cm and
the perimeters (circumference) of its circular ends
are 18 cm and 6 cm. Find the curved surface area of
the frustum.
$\sqrt{144}$
​

Answer 1

Answer:

Step-by-step explanation:

The slant height of a frustum of a cone is 4 c m and the perimeters (circumference) of its circular ends are 1 8 c m and 6 c m. Find the curved surface area of the frustum. Find the curved surface area of the frustum.

Answer 2

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The slant height of a frustum of a cone is 4 cm and

the perimeters (circumference) of its circular ends

are 18 cm and 6 cm. Find the curved surface area of

the frustum.

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Given:-

l=4 cm

Circumference of a circular end =18 cm

⇒2πr 1 =18

⇒π×r1=218=9 ...............................(1)

Circumference of other circular end =6 cm

⇒2πr2=6

⇒πr 2 = 26 =3..........................................(2)

Adding (1) and (2) Curved surface area.

=π(r1+r2)l

=(9+3)×4

=48 cm2

$\huge{\underline{\mathtt{\red{❥HO}\pink{PE}\green{IT'S}\blue{HE}\purple{LP}\orange{FUL}}}}$

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