The slant height of a frustum of a cone is 4 m and the perimeter of circular ends are 18 m and 16 m. Find the cost of painting its curved surface area at ₹100 per sq. m.
Answers
Step-by-step explanation:
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Given : The slant height of a frustum of a cone is 4 m and the perimeter of circular ends are 18 m and 16 m
To Find : The cost of painting it's curved surface area at Rs. 100 sq. m
Solution:
curved surface area of frustum of a cone = π(R + r) l
R = Radius of Base
r = Radius of top
l = slant height
perimeter of circular ends are 18 m and 16 m
=> 2πR = 18 and 2πr = 16
=> 2πR + 2πr = 18 + 16
=> 2π(R + r) = 34
=> π(R + r) = 17
l = 4
curved surface area of frustum of a cone = π(R + r) l
= 17 * 4
= 68 m²
cost of painting Rs. 100 sq. m
Hence total cost = 68 * 100 = 6800 Rs
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