Question

the slant height of a frustum of a cone is 5 cm if the difference of the radius of two circular and is 4 cm find the height of the frustum

Answer 1

Answer:

Height = 3 cm

Step-by-step explanation:

Here Slant Height of Frustum of Cone (L) = 5 cm

Difference of Radii of  two circular ends (R - r) = 4 cm

Let Height of the frustum of cone be H

We know that

$L =\sqrt{H^2+(R-r)^2}$

Putting values

$5=\sqrt{H^2+4^2$

Squaring both sides

25 = H² + 16

H² = 25 - 16

H² = 9

Taking Square Root of both sides

H = 3

∴ Height of the frustum of the cone is 3 cm