Question

the slant height of frustum of a cone is 10 cm if the height of frustum is 8 cm then find the difference of radii of its two circular ends

Answer 1

As we know that in frustum's slant height is equal to given formula l^2=h^2+(r1-r2)^2
That's why answer is 6
And solution is inside the pic

Answer 2

Answer:

The difference of radii of its two circular ends is 6 cm.

Step-by-step explanation:

Given : The slant height of frustum of a cone is 10 cm if the height of frustum is 8 cm.

To find : The difference of radii of its two circular ends?

Solution :

We know, the relationship between slant height, height and radius

i.e, $l^2=h^2+(r)^2$

Let R and r be the radius of two circular ends.

l slant height is l=10 cm

h height is h=8 cm

$l^2=h^2+(R-r)^2$

$10^2=8^2+(R-r)^2$

$100=64+(R-r)^2$

$(R-r)=\sqrt{36}$

$R-r=6$

Therefore, The difference of radii of its two circular ends is 6 cm.