the slant height of the frustum of a cone is 5 cm if the difference of the Radii of its two circular end is 4 centimetre find the height of the frustum
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16
______Heyy Buddy ❤________
_____Here's your Answer ________
Given;
R1 - R2 = 4 cm.
Slant Height = 5 cm.
Now,
l^2 = ( R1 - R2)^2 + h^2
=> 5^2 = 4^2 + h^2
=> h^2 = 25 - 16
=> h^2 = 9
=> h = 3 cm.
✔✔✔
_____Here's your Answer ________
Given;
R1 - R2 = 4 cm.
Slant Height = 5 cm.
Now,
l^2 = ( R1 - R2)^2 + h^2
=> 5^2 = 4^2 + h^2
=> h^2 = 25 - 16
=> h^2 = 9
=> h = 3 cm.
✔✔✔
Answered by
2
R1 - R2 = 4 cm.
Slant Height = 5 cm.
Now,
l²= ( R1 - R2)²+ h²
=> 5² = 4² + h²
=> h² = 25 - 16
=> h² = 9
=> h = 3 cm.
thank you
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