Physics, asked by anweshapanda20, 25 days ago

The slits in Young's double slit experiment are illuminated by light of wavelength 6000 Å. If the path difference at the central bright fringe is zero, what is the path difference for light from the slits at the fourth bright fringe ?
A) 2.4 x 10-6 m
B )1.2 x 10-6 m
C )10-6 m
D )0.5 x 10-5 m​

Answers

Answered by F55omkar
1

Answer:

(A)

Explanation:

The path difference at the centre is zero. The path difference at the 4th bright fringe=4λ

Here, λ=6000×10−10m

∴ Path difference =4×10−10=24×10−7

=2.4×10−6m

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