Question

The slope of a line joining P(6,k) and Q(1-3k,3) is 1/2 find k.​

Answer 1

Heya!!

Here's your answer!!

Given points are P(6, k) and Q(1 - 3k, 3).

Since, slope of line joining these two points = 1/2

therefore,

(Slope = y2 - y1/x2 - x1 )

3 - k/1 - 3k - 6 = 1/2

= 3 - k/ -3k - 5 = 1/2

= 6 -2k = -5 -6

= k = -11.

Glad help you,

it helps you,

thanks.

Answer 2

Answer:

Slope of PQ =

$\frac{3 - k }{1 -3k - 6}$

$\frac{1}{2} = \frac{3 - k}{1 - 3k - 6}$

$\frac{1}{2} = \frac{3 - k}{ - 3k - 5}$

$- 3k - 5 = 6 - 2k$

$k = - 11$