Question

The slope of a line perpendicular to the line passing through the points (2, 5) and (-3, 6) is
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Answer 1

Correct QuestioN :

The slope of point passing through the point (2, 5) and (-3, 6) is

SolutioN :

Let,

• The given Point be A( 2 , 5 )
• B( - 3 , 6 )

We know.

$\tt \dagger \: \: \: \: \: Slope \: of \: AB = \dfrac{ \Delta y}{\Delta x} = \dfrac{ y_2 - y_1}{ x_2 - x_1}$

Where as,

• x1 = 2.
• x2 = - 3.
• y1 = 5.
• y2 = 6.

Now,

$\tt \dagger \: \: \: \: \: Slope \: of \: AB = \dfrac{ y_2 - y_1 }{ x_2 - x_1 }$

$\tt : \implies Slope \: of \: AB = \dfrac{6 - 5}{ - 3 - 2}$

$\tt : \implies Slope \: of \: AB = \dfrac{1}{ -5}$

Therefore, the Slope of point passing the point be ( - 1 / 5 )

$\rule{90}2$

$\tt \dagger \: \: \: \: \:Formula\: Use :$

$\tt Slope \: of \: AB = \dfrac{ \Delta y}{\Delta x} = \dfrac{ y_2 - y_1}{ x_2 - x_1}$

Answer 2

Answer:

-1

perpendicular lines meet at a point to form right angles