Question

the slope of a line through A(2,3) is 3/4.Find the points on the line that are 5 units away from A

Answer 1

In the line, there will be two points which are at a distance of 5 unit from A(2,3)
If we go forward or backward  5 units in a line with slope 3/4, 

change in x-coordiante = $(\frac{4}{ \sqrt{3^{2}+4^{2}} })*5= \frac{4}{5}*5=4$

change in y-coordinate = $(\frac{3}{ \sqrt{3^{2}+4^{2}} })*5= \frac{3}{5}*5=3$

So if we go forward 5 units, the point will be (2+4,3+3) or (6,6)
    if we go backward 5 units, the point will be (2-4,3-3) or (-2,0)

Answer 2

Answer:

forward 5 units-(6,6)

backward 5 units-(-2,0)