the slope of a straight line passing through A (3,-4) is 5/12 the points on the line that are 26 unit away from A are
sai973:
answer is (27,6), (-21,-14)
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Answer:
(27,6) (-21,-14)
Step-by-step explanation:
We need to know the parametric form of representing a straight line:
Equation of line passing through (x₁,y₁) and making inclination ∅ with the positive x-axis is given by
x-x₁/cos∅ = y-y₁/sin∅ = r(parameter).
Now, r parameter represents the movement along the line. r can take positive or negative values depending on which side of (x₁,y₁) one is traversing.
So, (x,y) in parametric form would be
(x₁ ± rcos∅ , y₁±rsin∅ )
Now given r =26 Point(3,-4),
Given tan∅ = 5/12,
so sin∅ = 5/13, cos∅ = 12/13
(x,y) = (3±26*12/13,-4±26*5/13)
=(3±24,-4±10)
=(3+24,-4+10) or (3-24,-4-10)
=(27,6) or (-21,-14).
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