The slope of a tangent to a curve y = f(x) at [x, f(x)] is 2x + 1. If the curve passes through the point (1, 2), then the area bounded by the curve, the x-axis and the line x = 1 is
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Step-by-step explanation:
slope pf tangent =f'(x)
d/dx (2x^6+x^4-1)
2×d/dx (x)^6+ d/dx (x^4)-d/dx (1)
12x^5 + 4x^3
Slope of tangent at x=1
12 (1)^5 +4 (1)^3
12+4
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